how to solve five digit Square IBPS

how to solve five digit Square in less time

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Now we will go to the Topic How to square a number easily

First we are starting this topic we just learn three basic formula’s for this topic

  1. (A+B)^2             =(A^2)+(B^2)+(2*A*B)
  2. (A+B)^2             =(A^2)+(B^2)-(2*A*B)
  3. (A^2)-(B^2)       =(A+B)(A-B)

Now we will practice some problems on this

Based on Formala -1

Ex:-  (102)^2=?

Ans)   According to Formula we will devide 102 into  100+2
        (102)^2         =  (100+2)^2
                              =  (100)^2+(2)^2+(2*100*2)
                              =  10000+4+400
         (102)^2        =  10404
      Like that we can solve 5-disit number also

Based on Formala -2

Ex:-  (98)^2=?
Ans)   According to Formula we will devide 98 into  100-2
        (98)^2           =  (100-2)^2
                              =  (100)^2+(2)^2-(2*100*2)
                              =  10000+4-400
           (98)^2        =  9604
      Like that we can solve 5-disit number also

Based on Formala -3


Ex:-  (95)^2-(5)^2=?

Ans)   According to Formula we will write it as (95)^2-(5)^2  =  (95+5)(95-5)

         
           (95)^2-(5)^2     =   (95+5)(95-5)
                                     =    100*90
                                     =    9000
India

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